Homework

9.13 A. Ho : u<42 Ho : u>42 B. z= 42.95-42/2.64/ square root of 65 = 0.95/0.33=2.87. .10 =Ho>Ha .05=Ho>Ha .01=Ho>Ha .001=Ho<Ha C. 1-0.9979=0.0021 .10 =Ho>Ha .05=Ho>Ha .01=Ho>Ha .001=Ho<Ha D. in that location is extremely knock-down(prenominal) evidence 9.22 When scrutinying a hypothesis most populations mean to specify whether to use a z test or a test simply comes down to whether o is cognize or not. If it is unknown you use a t test is it is known you use a z test. 12.10 A. It is withdraw to carry forth a chi-square test using these selective information because it is gener everyy hold that n should be considered large if solely of the expected cubicle frequencies are at least 5. In this problem all of the Ei values are greater than or equal to 5. B.

I reason out that I cannot winnow out the pi values found in our problem, since it is much larger. 12.18 (a) A. I cerebrate that I cannot despise the pi values found in our problem, since it is much larger. Depreciation method and country are curtail and the test is valid. You can see this because since the p-value is much greater than .05 we cannot reject the hypothesis of normality at the .05 level of significance.If you want to rat a full essay, order it on our website: OrderCustomPaper.com

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